Let P be the point on the parabola,

Question:

Let $\mathrm{P}$ be the point on the parabola, $\mathrm{y}^{2}=8 \mathrm{x}$ which is at a minimum distance from the cente $\mathrm{C}$ of the circle, $\mathrm{x}^{2}+(\mathrm{y}+6)^{2}=1$. Then the equation of the circle, passing through $\mathrm{C}$ and having its centre at $\mathrm{P}$ is :

  1. $x^{2}+y^{2}-4 x+9 y+18=0$

  2. $x^{2}+y^{2}-4 x+8 y+12=0$

  3. $x^{2}+y^{2}-x+4 y-12=0$

  4. $x^{2}+y^{2}-\frac{x}{4}+2 y-24=0$


Correct Option: , 2

Solution:

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