Let y=y(x) be the solution of the differential

Question:

Let $y=y(x)$ be the solution of the differential equation, $\left(x^{2}+1\right)^{2} \frac{d y}{d x}+2 x\left(x^{2}+1\right) y=1$ such

that $y(0)=0$. If $\sqrt{a} y(1)=\frac{\pi}{32}$, then the value of 'a' is:

  1. $\frac{1}{2}$

  2. $\frac{1}{16}$

  3. $\frac{1}{4}$

  4. 1


Correct Option: , 2

Solution:

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