which option the order of reducing


 which option the order of reducing

power is correct.

EᶱCr2O72-/Cr3+ = 1.33V

EᶱMnO4/Mn2+ = 1.51V

EᶱCl2/Cl = 1.36V

EᶱCr3+/Cr = -0.74V

(i) Cr3+ < Cl–< Mn2+ < Cr

(ii) Mn2+ < Cl–< Cr3+ < Cr

(iii) Cr3+ < Cl–< Cr2O72– < MnO4–\

(iv) Mn2+ < Cr3+ < Cl–< Cr


Option (ii) is the answer.

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