On which axis do the following points lie?
(a) $\mathrm{P}(5,0)$
(b) $Q(0-2)$
(c) $R(-4,0)$
(d) $S(0,5)$
According to the Rectangular Cartesian Co-ordinate system of representing a point (x, y),
If $x>0, y>0$ then the point lies in the $1^{\text {st }}$ quadrant
If $x<0, y>0$ then the point lies in the $2^{\text {nd }}$ quadrant
If $x<0, y<0$ then the point lies in the $3^{\text {rd }}$ quadrant
If $x>0, y<0$ then the point lies in the $4^{\text {th }}$ quadrant
But in case
If $x=0, y \neq 0$ then the point lies on the $y$-axis
If $y=0, x \neq 0$ then the point lies on the $x$-axis
(i) Here the point is given to be $P(5,0)$. Comparing this with the standard form of
$(x, y)$ we have
$x=5$
$y=0$
Here we see that $y=0, x \neq 0$
Hence the given point lies on the $x$-axis
(ii) Here the point is given to be $Q(0,--2)$. Comparing this with the standard form of $(x, y)$ we have
$x=0$
$y=-2$
Here we see that $x=0, y \neq 0$
Hence the given point lies on the $y$-axis
(iii) Here the point is given to be $R(-4,0)$. Comparing this with the standard form of $(x, y)$ we have
$x=-4$
$y=0$
Here we see that $y=0, x \neq 0$
Hence the given point lies on the $x$-axis
(iv) Here the point is given to be $S(0,5)$. Comparing this with the standard form of $(x, y)$ we have
$x=0$
$y=5$
Here we see that $x=0, y \neq 0$
Hence the given point lies on the $y$-axis