Out of all the patients in a hospital 89 % are found to be suffering from heart ailment and 98 % are suffering from lungs infection. If K % of them are suffering from both ailments, then K can not belong to the set :

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Question:

Out of all the patients in a hospital $89 \%$ are found to be suffering from heart ailment and $98 \%$ are suffering from lungs infection. If $\mathrm{K} \%$ of them are suffering from both ailments, then $K$ can not belong to the set :

  1. $\{80,83,86,89\}$

  2. $\{84,86,88,90\}$

  3. $\{79,81,83,85\}$

  4. $\{84,87,90,93\}$


Correct Option: , 3

Solution:

$n(A \cup B) \geq n(A)+n(B)-n(A \cap B)$

$100 \geq 89+98-n(A \cup B)$

$n(A \cup B) \geq 87$

$87 \leq \mathrm{n}(\mathrm{A} \cup \mathrm{B}) \leq 89$

Option (3)

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Feb. 14, 2023, 3:37 p.m.
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