P is any point on the side BC of a ∆ABC. P is joined to A.


P is any point on the side BC of a ∆ABCis joined to A. If D and E are the midpoints of the sides AB and AC respectively and and are the midpoints of BP and CP respectively then quadrilateral DENM is
(a) a trapezium
(b) a parallelogram
(c) a rectangle
(d) a rhombus



Given: In ∆ABCMND and E are the mid-points of BP, CP, AB and AC, respectivley.

In ∆ABP,

"> D and M are the mid-points of AB,and BP, respectively.      (Given)

$\therefore B M=\frac{1}{2} A P$ and $B M \| A P$       (Mid-point theorem)       ...(i)

Again, in ∆ACP,

$\because E$ and $N$ are the mid-points of $A C$, and $C P$, respectively.       (Given)

$\therefore E N=\frac{1}{2} A P$ and $E N \| A P$   (Mid-point theorem)       ...(ii)

From (i) and (ii), we get

BM = EN and BM || EN

But this a pair of opposite sides of the quadrilateral DENM.

So, DENM is a parallelgram.

Hence, the correct option is (b).





Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now