Question:
pH of 0.08 mol dm-3 HOCl solution is 2.85. Calculate its ionisation constant.
Solution:
Given, pH =2.85 and C =0.08 mol dm-3
Now since HOCl is a weak acid its dissociation will be given as-
HOCl + H2O ⇌ H30+ + OCl-
We know that;
pH = -log [H+]
-2.85 = log [H+] [H+] = antilog (-2.85)
[H+] = 1.41 × 10-3
We also know that, for a weak mono basic acid-
(On squaring both sides) [H+]2 = kaC
Ka = (1.41 x 10-3)2/ 0.08 = 2.5 × 10-5
Hence the ionization constant of HOCl will be 2.5 × 10-5
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- JEE Main
- Exam Pattern
- Previous Year Papers
- PYQ Chapterwise
- Physics
- Kinematics 1D
- Kinemetics 2D
- Friction
- Work, Power, Energy
- Centre of Mass and Collision
- Rotational Dynamics
- Gravitation
- Calorimetry
- Elasticity
- Thermal Expansion
- Heat Transfer
- Kinetic Theory of Gases
- Thermodynamics
- Simple Harmonic Motion
- Wave on String
- Sound waves
- Fluid Mechanics
- Electrostatics
- Current Electricity
- Capacitor
- Magnetism and Matter
- Electromagnetic Induction
- Atomic Structure
- Dual Nature of Matter
- Nuclear Physics
- Radioactivity
- Semiconductors
- Communication System
- Error in Measurement & instruments
- Alternating Current
- Electromagnetic Waves
- Wave Optics
- X-Rays
- All Subjects
- Physics
- Motion in a Plane
- Law of Motion
- Work, Energy and Power
- Systems of Particles and Rotational Motion
- Gravitation
- Mechanical Properties of Solids
- Mechanical Properties of Fluids
- Thermal Properties of matter
- Thermodynamics
- Kinetic Theory
- Oscillations
- Waves
- Electric Charge and Fields
- Electrostatic Potential and Capacitance
- Current Electricity
- Thermoelectric Effects of Electric Current
- Heating Effects of Electric Current
- Moving Charges and Magnetism
- Magnetism and Matter
- Electromagnetic Induction
- Alternating Current
- Electromagnetic Wave
- Ray Optics and Optical Instruments
- Wave Optics
- Dual Nature of Radiation and Matter
- Atoms
- Nuclei
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- Chemical Effects of Electric Current,
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