Question:
$x^{2}+12 x+35=0$
Solution:
Given :
$x^{2}+12 x+35=0$
$\Rightarrow x^{2}+7 x+5 x+35=0$
$\Rightarrow x(x+7)+5(x+7)=0$
$\Rightarrow(x+5)(x+7)=0$
$\Rightarrow x+5=0$ or $x+7=0$
$\Rightarrow x=-5$ or $x=-7$
Hence, $-5$ and $-7$ are the roots of the equation $x^{2}+12 x+35=0$.
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