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# Radiation of wavelength $lambda$, is incident on a photocell.

Question:

Radiation of wavelength $\lambda$, is incident on a photocell. The fastest emitted electron has speed $\mathrm{v}$. If the wavelength of changed to $\frac{3 \lambda}{4}$, the speed of the fastest emitted electron will be :-

1. $=v\left(\frac{3}{5}\right)^{1 / 2}$

2. $>v\left(\frac{4}{3}\right)^{1 / 2}$

3. $4.$=v\left(\frac{4}{3}\right)^{1 / 2}\$

Correct Option: , 2

Solution: