Question:
Show that $(x+2)$ is a factor of $f(x)=x^{3}+4 x^{2}+x-6$
Solution:
Given: $f(x)=x^{3}+4 x^{2}+x-6$
Now, $f(-2)=(-2)^{3}+4(-2)^{2}+(-2)-6$
$=-8+16-2-6$
$=0$
$\therefore(x+2)$ is a factor of $f(x)=x^{3}+4 x^{2}+x-6$.
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.