Solve the following:

Question:

Find the area bounded under the curve $y=3 x^{2}+6 x+7$ and the X-axis with the co-ordinates at $x=5$ and $x=10$.

Solution:

$y=3 x^{2}+6 x+7$

Area bounded under the curve within $x=5$ and $x=10$ is calculated by the method of integration.

Area $=\int_{x=0}^{x-\pi} y d x=\int_{x=0}^{x-\pi} \sin x d x=-[\cos \pi-\cos 0]=2$

 

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