Solve the following :

take $O$ as $(0,0)$

brick $A$ and $E$ is from $\left(\frac{L}{10}\right.$ to $\left.L+\frac{L}{10}\right)$

brick $B$ and $D$ is from $\left(\frac{2 L}{10}\right.$ to $\left.L+\frac{2 L}{10}\right)$

brick $C$ is from $\left(\frac{3 L}{10}\right.$ to $\left.L+\frac{3 L}{10}\right)$

$1^{\text {st }}, F$ are from $(0$ to $L)$

For $1^{s t}$ and F bricks, C.O.M= $\left(\frac{L}{2}\right)$

For $B$ and D, C.O.M $=\left(\frac{L}{2}+\frac{2 L}{10}\right)$

(as they are displaced by $\frac{}{\frac{2 L}{10}}$ )

Similarly,

For $A$ and E C.O.M $=\left(\frac{L}{2}+\frac{L}{10}\right)$

For C, C.O.M $=\left(\frac{L}{2}+\frac{3 L}{10}\right)$