Question:
Solve $\frac{|x-2|}{x-2}>0$
Solution:
We have,
$\frac{|x-2|}{x-2}>0$
As, $|x-2|=\left\{\begin{array}{l}x-2, x \geq 2 \\ 2-x, x<2\end{array}\right.$
And $\frac{|x-2|}{x-2}>0$ for $x>2$
So, $x>2$
$\therefore x \in(2, \infty)$
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