Solve the following :


Suppose the bob of the previous problem has a speed of $1.4 \mathrm{~m} / \mathrm{s}$ when the string makes an angle of $0.20$ radian with the vertical. Find the tension at this instant. You can use $\cos \theta=1-\theta^{2} / 2$ and $\sin \theta=$ 0 for small $\theta$.


At angle $\theta$

$T=m g \cos \theta+\frac{m v^{2}}{R}$

$\mathrm{T}=\operatorname{mg}\left(1-\frac{\theta^{2}}{2}\right)+\frac{m v^{2}}{R}$


$\mathrm{T} \simeq 1.16$

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