Solve the following


$6.023 \times 10^{22}$ molecules are present in $10 \mathrm{~g}$ of a substance ' $x$ '. The molarity of a solution containing $5 \mathrm{~g}$ of substance ' $x$ ' in $2 \mathrm{~L}$ solution is______________  $\times 10^{-3}$. 



Number of mole of $x=\frac{6.022 \times 10^{22}}{6.022 \times 10^{23}}=\frac{10}{\text { Molar mass of } x}$

So molar mass of $x=100 \mathrm{~g}$

Molarity $=\frac{5}{100 \times 2}=0.025 \mathrm{M}$.

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