Question:
Why is $K_{\mathrm{a}_{2}} \ll K_{\mathrm{a}_{1}}$ for $\mathrm{H}_{2} \mathrm{SO}_{4}$ in water?
Solution:
It can be noticed that 
This is because a neutral H2SO4 has a much higher tendency to lose a proton than the negatively charged 
. Thus, the former is a much stronger acid than the latter.