Solve the following :


If the horizontal force needed for the turn in the previous problem is to be supplied by the normal force by the road, what should be the proper angle of banking?


Let banking angle be $\theta$

$\tan \theta=\frac{v^{2}}{R g}$

$\tan \theta=\frac{\left(36 \times \frac{5}{18}\right)^{2}}{30 \times 10}=\frac{1}{3}$

$\theta=\tan -1\left(\frac{1}{3}\right)$


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