Solve the following :

For mass $0.5 \mathrm{Kg}$

$m g-T=m a$

$0.5 g-T=0.5 a-(i)$

for $1 \mathrm{Kg}$ night mass

$T-T_{1}-\mu N=m a$

$T-T_{1}-0.2 \times 10=1 \times a$

$T-T_{1}=2+a \quad-(i i)$

For $1 \mathrm{Kg}$ left mass

$T_{1}-\mu N=m a$

$T_{1}-0.2 \times 10=1 \times a-(i i i)$

$a=0.4 \mathrm{~m} / \mathrm{s}^{2}$

$T_{1}=2.4 \mathrm{~N}$

$T_{2}=4.8 \mathrm{~N}$