Solve the following

Question:

Let $\cos (\alpha+\beta)=\frac{4}{5}$ and let $\sin (\alpha-\beta)=\frac{5}{13}$, where $0 \leq \alpha, \beta \leq \frac{\pi}{4}$. Then $\tan 2 \alpha=$

  1. $\frac{25}{16}$

  2. $\frac{56}{33}$

  3. $\frac{19}{12}$

  4. $\frac{20}{7}$


Correct Option: , 2

Solution:

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