Question: Let $\cos (\alpha+\beta)=\frac{4}{5}$ and let $\sin (\alpha-\beta)=\frac{5}{13}$, where $0 \leq \alpha, \beta \leq \frac{\pi}{4}$. Then $\tan 2 \alpha=$
$\frac{25}{16}$
$\frac{56}{33}$
$\frac{19}{12}$
$\frac{20}{7}$
Correct Option: , 2
Solution:
