Solve the following

Question:

[P] on treatment with $\mathrm{Br}_{2} / \mathrm{FeBr}_{3}$ in $\mathrm{CCl}_{4}$ produced a single isomer $\mathrm{C}_{8} \mathrm{H}_{7} \mathrm{O}_{2} \mathrm{Br}$ while heating $[\mathrm{P}]$ with sodalime gave toluene. The compound [P] is :


Correct Option:

Solution:

A certain orbital has no angular nodes and two radial nodes. The orbital is:

(1) $2 \mathrm{~s}$

(2) $3 \mathrm{~s}$

(3) $3 \mathrm{p}$

(4) $2 \mathrm{p}$

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