# Solve the following

Question:

$10.30 \mathrm{mg}$ of $\mathrm{O}_{2}$ is dissolved into a liter of sea water of density $1.03 \mathrm{~g} / \mathrm{mL}$. The concentration of $\mathrm{O}_{2}$ in ppm is ______________ .

Solution:

(10.00)

$\mathrm{ppm}=\frac{10.3 \times 10^{-3}}{1.03 \times 1000} \times 10^{6}=10$