Question:
$\mathrm{AB}_{2}$ is $10 \%$ dissociated in water to $\mathrm{A}^{2+}$ and $\mathrm{B}^{-}$. The boiling point of a $10.0$ molal aqueous solution of $\mathrm{AB}_{2}$ is______________ . ${ }^{\circ} \mathrm{C}$. (Round off to the Nearest Integer). [Given : Molal elevation constant of water $\mathrm{K}_{\mathrm{b}}=0.5 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$ boiling point of pure water $\left.=100^{\circ} \mathrm{C}\right]$
Solution:
(106)
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.