# Solve the following

Question:

How are XeO3 and XeOF4 prepared?

Solution:

(i) XeO3 can be prepared in two ways as shown.

$6 \mathrm{XeF}_{4}+12 \mathrm{H}_{2} \mathrm{O} \longrightarrow 4 \mathrm{Xe}+2 \mathrm{XeO}_{3}+24 \mathrm{HF}+3 \mathrm{O}_{2}$

$\mathrm{XeF}_{6}+3 \mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{XeO}_{3}+6 \mathrm{HF}$

(ii) XeOF4 can be prepared using XeF6.

$\mathrm{XeF}_{6}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{XeOF}_{4}+2 \mathrm{HF}$