Question:
Solve the following quadratic equations by factorization:
$3 x^{2}=-11 x-10$
Solution:
We have been given
$3 x^{2}=-11 x-10$
$3 x^{2}+11 x+10=0$
$3 x^{2}+6 x+5 x+10=0$
$3 x(x+2)+5(x+2)=0$
$(3 x+5)(x+2)=0$
Therefore,
$3 x+5=0$
$3 x=-5$
$x=\frac{-5}{3}$
or,
$x+2=0$
$x=-2$
Hence, $x=\frac{-5}{3}$ or $x=-2$.
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