Question:
The proposition $\mathrm{p} \rightarrow \sim(\mathrm{p} \wedge \sim \mathrm{q})$ is equivalent to:
Correct Option: 1
Solution:
$\mathrm{p} \rightarrow \sim(\mathrm{p} \wedge \sim \mathrm{q})$
$=\sim p \vee \sim(p \wedge \sim q)$
$=\sim p \vee \sim p \vee q$
$=\sim(p \wedge q) \vee q$
$=\sim p \vee q$
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