Question:
$\int_{-\pi}^{\pi}|\pi-| x|| d x$ is equal to :
Correct Option: 1
Solution:
$\int_{-\pi}^{\pi}|\pi-| x|| d x=2 \int_{0}^{\pi}|\pi-x| d x$
$=2 \int_{0}^{\pi}(\pi-x) d x$
$=2\left[\pi x-\frac{x^{2}}{2}\right]_{0}^{\pi}=\pi^{2}$
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