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Find the $6^{\text {th }}$ and $n$th terms of the GP $2,6,18,54 \ldots$


Given: GP is 2, 6, 18, 54….

The given GP is of the form, $a, a r, a r^{2}, a r^{3} \ldots$

Where r is the common ratio.

First term in the given GP, $a_{1}=a=2$

Second term in GP, $a_{2}=6$

Now, the common ratio, $r=\frac{a_{2}}{a_{1}}$


 Now, $\mathrm{n}^{\text {th }}$ term of GP is, $a_{n}=a r^{n-1}$

So, the $6^{\text {th }}$ term in the GP,


$=2 \times 3^{5}$


$\mathrm{n}^{\text {th }}$ term in the GP,

$a_{n}=a r^{n-1}$


Hence, $6^{\text {th }}$ term $=486$ and $n^{\text {th }}$ term $=2.3^{n-1}$


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