Solve this
Question:

The $\mathrm{K}_{\mathrm{sp}}$ for $\mathrm{Cr}(\mathrm{OH})_{3}$ is $1.6 \times 10^{-30}$. The molar solubility of this compound in water is :-

  1. $\sqrt[2]{1.6 \times 10^{-30}}$

  2. $\sqrt[4]{1.6 \times 10^{-30}}$

  3. $\sqrt[4]{1.6 \times 10^{-30} / 27}$

  4. $1.6 \times 10^{-30} / 27$


Correct Option: , 3

Solution:

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