Solve this


When $p(x)=x^{3}-3 x^{2}+4 x+32$ is divided by $(x+2)$, the remainder is

(a) 0

(b) 32

(c) 36

(d) 4



(d) 4

$x+2=0 \Rightarrow x=-2$

By the remainder theorem, we know that when p(x) is divided by (x + 2), the remainder is p(-">-2).
Now, we have:

$p(-2)=(-2)^{3}-3 \times(-2)^{2}+4 \times(-2)+32$



Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now