Solve this following

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Question:
The structure of $\mathrm{PCl}_{5}$ in the solid state is

square pyramidal
tetrahedral $\left[\mathrm{PCl}_{4}\right]^{+}$and octahedral $\left[\mathrm{PCl}_{6}\right]^{-}$
square planar $\left[\mathrm{PCl}_{4}\right]^{+}$and octahedral $\left[\mathrm{PCl}_{6}\right]^{-}$
trigonal bipyramidal

Correct Option: , 2

Solution:

$\mathrm{PCl}_{5(\mathrm{~s})}$ exist as $\left[\mathrm{PCl}_{4}\right]^{+}$and $\left[\mathrm{PCl}_{6}\right]^{-}$