Question:
$\operatorname{Ge}(Z=32)$ in its ground state electronic configuration has x completely filled orbitals with $\mathrm{m}_{l}=0 .$ The value of $\mathrm{x}$ is
Solution:
Completely filled orbital with $\mathrm{m}_{t}=0$ are
$=1+1+1+1+1+1+1$
$=7$
So Answer is 7
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