Solve this following


Mark $(\sqrt{)}$ against the correct answer in the following:

If $y=\sqrt{x \sin x}$ then $\frac{d y}{d x}=?$

A. $\frac{(x \cos x+\sin x)}{2 \sqrt{x \sin x}}$

B. $\frac{1}{2}(x \cos x+\sin x) \cdot \sqrt{x \sin x}$

C. $\frac{1}{2 \sqrt{x \sin x}}$

D. none of these


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