Solve this following


The vertices $\mathrm{B}$ and $\mathrm{C}$ of a $\triangle \mathrm{ABC}$ lie on the line,

$\frac{x+2}{3}=\frac{y-1}{0}=\frac{z}{4}$ such that $B C=5$ units. Then the

area (in sq. units) of this triangle, given that the point $\mathrm{A}(1,-1,2)$, is :-


  1. $2 \sqrt{34}$

  2. $\sqrt{34}$

  3. 6

  4. $5 \sqrt{17}$

Correct Option: , 2



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