Question:
Let $\mathrm{A}$ and $\mathrm{B}$ be two events such that $\mathrm{P}(\overline{\mathrm{A} \cup \mathrm{B}})=\frac{1}{6}, \mathrm{P}(\mathrm{A} \cap \mathrm{B})=\frac{1}{4}$ and $\mathrm{P}(\overline{\mathrm{A}})=\frac{1}{4}$, Where $\overline{\mathrm{A}}$ stands for the complement of the event $A$. Then the events $A$ and $B$ are :
Correct Option: , 3
Solution: