Solve this following

Question:

For the reaction of $\mathrm{H}_{2}$ with $\mathrm{I}_{2}$, the rate constant is $2.5 \times 10^{-4} \mathrm{dm}^{3} \mathrm{~mol}^{-1} \mathrm{~s}^{-1}$ at $327^{\circ} \mathrm{C}$ and $1.0 \mathrm{dm}^{3} \mathrm{~mol}^{-1} \mathrm{~s}^{-1}$ at $527^{\circ} \mathrm{C}$. The activation energy for the reaction, in $\mathrm{kJ} \mathrm{mol}^{-1}$ is: $\left(\mathrm{R}=8.314 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right)$

  1. 72

  2. 166

  3. 150

  4. 59


Correct Option: , 2

Solution:

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