Solve this following


Mark $(\sqrt{)}$ against the correct answer in the following:

The value of $\mathrm{k}$ for which $f(\mathrm{x})=\left\{\begin{array}{c}\frac{\sin 5 \mathrm{x}}{3 \mathrm{x}}, \text { if } \mathrm{x} \neq 0 \\ \mathrm{k}, \text { if } \mathrm{x}=0\end{array}\right.$ is continuous at $\mathrm{x}=0$ is

A. $\frac{1}{3}$

B. 0

C. $\frac{3}{5}$

D. $\frac{5}{3}$


Leave a comment


Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now