Solve this following


A resistor dissipates $192 \mathrm{~J}$ of energy in $1 \mathrm{~s}$ when a current of $4 \mathrm{~A}$ is passed through it. Now, when the current is doubled, the amount of thermal energy dissipated in $5 \mathrm{~s}$ in


$\mathrm{E}=i^{2} \mathrm{Rt}$


$\mathrm{R}=12 \Omega$


$=3840 \mathrm{~J}$


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