Solve this following

Question:

A granite rod of $60 \mathrm{~cm}$ length is clamped at its middle point and is set into longitudinal vibrations. The density of granite is $2.7 \times 10^{3} \mathrm{~kg} / \mathrm{m}^{3}$ and its Young's modulus is $9.27 \times 10^{10} \mathrm{~Pa}$. What will be the fundamental frequency of the longitudinal vibrations?

 

  1. $2.5 \mathrm{kHz}$

  2. $10 \mathrm{kHz}$

  3. $7.5 \mathrm{kHz}$

  4. $5 \mathrm{kHz}$


Correct Option: , 4

Solution:

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now