Solve this following


Mark $(\sqrt{ })$ against the correct answer in each of the following:

$\int \sin 3 x \sin 2 x d x=?$

A. $-\frac{1}{5} \cos 5 x+C$

B. $\frac{1}{2} \sin x+\frac{1}{10} \sin 5 x-C$

C. $\frac{1}{2} \sin x-\frac{1}{10} \sin 5 x-C$

D. $-\frac{1}{3} \cos 3 x-\frac{1}{2} \sin 2 x+C$


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