Solve this following
Question:

Mark $(\sqrt{ })$ against the correct answer in the following:

$f y=x^{\sqrt{x}}$ then $\frac{d y}{d x}=?$

A. $\sqrt{x} \cdot x^{(\sqrt{x}-1)}$

B. $\frac{x^{\sqrt{x}} \log x}{2 \sqrt{x}}$

C. $\mathrm{x}^{\sqrt{\mathrm{x}}}\left\{\frac{2+\log \mathrm{x}}{2 \sqrt{\mathrm{x}}}\right\}$

D. none of these

Solution:

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