Solve this following


The reaction of $\mathrm{H}_{3} \mathrm{~N}_{3} \mathrm{~B}_{3} \mathrm{Cl}_{3}$ (A) with $\mathrm{LiBH}_{4}$ in tetrahydrofuran gives inorganic benzene $(B)$. Further, the reaction of (A) with (C) leads to $\mathrm{H}_{3} \mathrm{~N}_{3} \mathrm{~B}_{3}(\mathrm{Me})_{3}$. Compounds (B) and (C) respectively, are:

  1. Boron nitride and $\mathrm{MeBr}$

  2. Borazine and $\mathrm{MeMgBr}$

  3. Borazine and MeBr

  4. Diborane and MeMgBr

Correct Option: , 2


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