Solve this following


Mark $(\sqrt{)}$ against the correct answer in each of the following:

$\int x \sin x \cos x d x=?$

A. $-\frac{1}{4} x \sin 2 x+\frac{1}{8} \cos 2 x+C$

B. $\frac{1}{4} x \cos 2 x-\frac{1}{8} \sin 2 x+C$

C. $\frac{1}{2} \mathrm{x} \sin 2 \mathrm{x}+\frac{1}{4} \cos 2 \mathrm{x}+\mathrm{C}$


D. $-\frac{1}{4} x \cos 2 x+\frac{1}{8} \sin 2 x+C$


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