Solve this following

Question:

Mark $(\sqrt{)}$ against the correct answer in the following:

If $\mathrm{y}=\sqrt{\frac{1+x}{1-x}}$ then $\frac{d y}{d x}=?$

A. $\frac{2}{(1-x)^{2}}$

B. $\frac{x}{(1-x)^{3 / 2}}$

C. $\frac{1}{(1-x)^{3 / 2} \cdot(1+x)^{1 / 2}}$

D. none of these

Solution:

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