Solve this following

Question:

If $\left(\begin{array}{cc}x-y & 2 x-y \\ 2 x+z & 3 z+w\end{array}\right)=\left(\begin{array}{cc}-1 & 0 \\ 5 & 13\end{array}\right)$ then

A. $z=3, w=4$

B. $z=4, w=3$

C. $z=1, w=2$

D. $z=2, w=-1$

Solution:

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