Solve this following

Question:

$50 \mathrm{~mL}$ of $0.5 \mathrm{M}$ oxalic acid is needed to neutralize $25 \mathrm{~mL}$ of sodium hydroxide solution. The amount of $\mathrm{NaOH}$ in $50 \mathrm{~mL}$ of the given sodium hydroxide solution is :

  1. $40 \mathrm{~g}$

  2. $20 \mathrm{~g}$

  3. $80 \mathrm{~g}$

  4. $10 \mathrm{~g}$


Correct Option:

Solution:

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