Solve this following Question

Question:

Let the line $\frac{\mathrm{x}-2}{3}=\frac{\mathrm{y}-1}{-5}=\frac{\mathrm{z}+2}{2}$ lie in the plane $\mathrm{x}+3 \mathrm{y}-\alpha \mathrm{z}+\beta=0$. Then $(\alpha, \beta)$ equals

  1. $(5,-15)$

  2.  $(-5,5)$

  3. $(6,-17)$

  4. $(-6,7)$


Correct Option: 1

Solution:

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