Solve this following Question

Let the line $\frac{\mathrm{x}-2}{3}=\frac{\mathrm{y}-1}{-5}=\frac{\mathrm{z}+2}{2}$ lie in the plane $\mathrm{x}+3 \mathrm{y}-\alpha \mathrm{z}+\beta=0$. Then $(\alpha, \beta)$ equals