Student A and Student B


Student A and Student B used two screw gauges of equal pitch and 100 equal circular divisions to measure the radius of a given wire. The actual value of the radius of the wire is $0.322 \mathrm{~cm}$. The absolute value of the difference between the final circular scale readings observed by the students A and $B$ is

[Figure shows position of reference 'O' when jaws of screw gauge are closed]

Given pitch $=0.1 \mathrm{~cm}$.


For (A)

Reading $=$ MSR $+$ CSR $+$ Error

$0.322=0.300+\mathrm{CSR}+5 \times \mathrm{LC}$



For B

Reading $=$ MSR $+$ CSR $+$ Error



Difference $=0.030-0.017=0.013 \mathrm{~cm}$

Division on circular scale $=\frac{0.013}{0.001}=13$

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Sourav sharma
May 29, 2022, 10:34 p.m.
Why MSR are 0.300 and 0.200
April 24, 2023, 6:35 a.m.
Why MSR are 0.300 and 0.200

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