# Suppose the acceleration due to gravity at a place

Question:

Suppose the acceleration due to gravity at a place is $10 \mathrm{~m} / \mathrm{s}^{2}$. Find its value in $\mathrm{cm} /(\text { minute })^{2}$.

Solution:

$\mathrm{g}=10 \mathrm{metre} / \mathrm{sec}^{2}=10 \times 100 \times 3600 \mathrm{~cm} / \mathrm{min}^{2} .=36 \times 10^{5} \mathrm{~cm} / \mathrm{min}^{2}$