Question:
The 8th term of an AP is 17 and its 14th term is 29. The common difference of the AP is
(a) 3
(b) 2
(c) 5
(d) −2
Solution:
( b) 2
T8 = a + 7d = 17 ...(i)
T14 = a + 13d = 29 ...(ii)
On subtracting (i) from (ii), we get:
⇒ 6d = 12
⇒ d = 2
Hence, the common difference is 2.
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