The acceleration due to gravity on the earth's surface

Question:

The acceleration due to gravity on the earth's surface at the poles is $\mathrm{g}$ and angular velocity of the earth about the axis passing through the pole is $\omega$. An object is weighed at the equator and at a height $\mathrm{h}$ above the poles by using a spring balance. If the weights are found to be same, then $h$ is : $(h<

  1. $\frac{\mathrm{R}^{2} \omega^{2}}{8 \mathrm{~g}}$

  2. $\frac{\mathrm{R}^{2} \omega^{2}}{4 \mathrm{~g}}$

  3. $\frac{\mathrm{R}^{2} \omega^{2}}{\mathrm{~g}}$

  4. $\frac{R^{2} \omega^{2}}{2 g}$

Correct Option: , 4

Solution:

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now

eSaral Gurukul

NEET

JEE Main

JEE Advanced

Our Telegram Channel

All Study Material